[nycphp-talk] array_diff that works both ways ?
Jon Baer
jonbaer at jonbaer.net
Sat Aug 2 16:23:04 EDT 2003
dont think u need to sort, u could just merge results:
$array1 = array(1,2,3);
$array2 = array(2,3,4);
$array3 = array_merge(array_diff($array1, $array2), array_diff($array2,
$array1));
print_r($array3);
but i think u r right there should be a "array_diff_recursive" method or
something.
- jon
pgp key: http://www.jonbaer.net/jonbaer.asc
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----- Original Message -----
From: "David Mintz" <dmintz at panix.com>
To: <chendry at nyc.rr.com>; "NYPHP Talk" <talk at lists.nyphp.org>
Sent: Saturday, August 02, 2003 10:04 AM
Subject: [nycphp-talk] array_diff that works both ways ?
>
> I'm wondering what's the most efficient way to find out if $array1 and
> $array2 contain exactly the same elements, without regard to order.
> array_diff(array1,array2) "returns an array containing all the values of
> array1 that are not present in any of the other arguments." according to
> TFM. Assuming
>
> $array1 = array(1,2,3);
> $array2 = array(2,3,4);
>
> then array_diff($array1,$array2) would return an array containing 1. I'd
> like to get one containing (1,4). I know I could sort them both and then
> test them for equality. I just wonder if there's a more efficient
> technique or if I'm overlooking some native function that does this.
>
> (FWIW, it's for a home-grown shopping cart kind of thing and the objective
> is to detect whether the array of product ids they just POSTed is any
> different from its counterpart in $_SESSION, to avoid doing needless
> database calls).
>
> Always gratefully,
>
>
> ---
> David Mintz
> http://davidmintz.org/
> Email: See http://dmintzweb.com/whitelist.php first!
>
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refrigerator: 190
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>
> -- Harper's Index, February 2003
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