NYCPHP Meetup

[Aaron Fischer]

I think it's simpler then that:

$foo="bar";

then:

echo $foo;
   will output the value of the variable

Aaron


On Friday, January 31, 2003, at 01:00 PM, Brian wrote:

> I was kinda wondering how that worked.  Doesn't really apply to the 
> original
> question then.  Answered one for me then, thanks.
>
> Brian
>
> On Friday 31 January 2003 12:51 pm, Jim Musil wrote:
>> I don't think so. I think this would allow the name of a variable to 
>> be
>> dynamic.
>>
>> eg:
>>
>> $foo = "bar";
>> $bar = "This is the value of my variable";
>>
>> ..
>>
>> echo $$foo;
>>
>> .. will output "This is the value of my variable"
>>
>>
>>
>> Jim Musil
>> <jim at nettmedia.com>
>> Nettmedia, Senior Developer
>> 345 Seventh Ave., 24th Floor.
>> New York, NY 10001
>> Tel. 212.629.0004 x 131
>>
>> On 1/31/03 12:41 PM, "Brian" <brian at preston-campbell.com> wrote:
>>> I have never used it, so I may be wrong, but I think what you need is
>>>
>>> $$variable
>>>
>>> On Friday 31 January 2003 12:37 pm, Jim Musil wrote:
>>>> It seems like it would be helpful if there were a way to grab the 
>>>> name
>>>> assigned to a variable and output it. Is there already a function 
>>>> like
>>>> this?
>>>>
>>>> I would use this mainly for tracing and reporting. So, if I had a 
>>>> simple
>>>> function show_variable($var), it would not only output the value
>>>> assigned to the variable, but would also show the name of the 
>>>> variable
>>>> itself.
>>>>
>>>> Am I missing it?
>>>>
>>>>
>>>> Jim Musil
>>>> <jim at nettmedia.com>
>>>> Nettmedia, Senior Developer
>>>> 345 Seventh Ave., 24th Floor.
>>>> New York, NY 10001
>>>> Tel. 212.629.0004 x 131
>>
>>
>
>
>
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