[nycphp-talk] MySQL Monitor V PHP & MySQL
PaulCheung
paulcheung at tiscali.co.uk
Sat Sep 22 12:20:46 EDT 2007
Hi everybody
I have implemented all the suggested changes and still cannot get it to work
maybe it is time to just hand over the code to see if anybody can see what I
am doing wrong.
What I am trying to do is get the value of ACCESS_CODE
Paul
----- Original Message -----
From: "Rick Retzko" <rick at click-rick.net>
To: "'NYPHP Talk'" <talk at lists.nyphp.org>
Sent: Saturday, September 22, 2007 3:57 PM
Subject: RE: [nycphp-talk] MySQL Monitor V PHP & MySQL
> Two errors that I can find:
>
> 1. You're missing the 'WHERE' key word in your SQL: $sql = "SELECT
> access_code
> FROM authorised_users
> user_id = '$userid' AND
> user_password = '$password' AND
> account = '$account'";
> should be:
> $sql = "SELECT access_code
> FROM authorised_users
> WHERE user_id = '$userid' AND
> user_password = '$password' AND
> account = '$account'";
>
> 2. Your mysql_num_rows is misspelled (Yours is mysql_numrows) making the
> subsequent 'if' statement FALSE.
>
> Hope this helps
>
>
> Rick
>
> -----Original Message-----
> From: talk-bounces at lists.nyphp.org [mailto:talk-bounces at lists.nyphp.org]
> On
> Behalf Of PaulCheung
> Sent: Friday, September 21, 2007 3:47 PM
> To: talk at lists.nyphp.org
> Subject: [nycphp-talk] MySQL Monitor V PHP & MySQL
>
> I have researched, checked and tried everything I can think of and still
> cannot get it to work.
>
> when using MySQL monitor the following works
> =================================
>
> SELECT access_code FROM authorised_users WHEN user_id = 'Nancy' AND
> user_password = 'qwerty' AND account = '48572998';
>
> Access_code is displayed = 11966552
>
> When using PHP & MySQL ($userid='Nancy', $user_password='qwerty',
> $account='48572998')
> ====================
> <?PHP session_start(); ob_start(); PHP?>
> <HTML><HEAD><TITLE>auth</TITLE></HEAD>
> <FORM action="X.php" id="primary" method="post"> <BODY> <?PHP
> $userid = $_POST['user'];
> $password = $_POST['passcode'];
> $account = $_POST['account'];
> $self = $_SERVER['PHP_SELF'];
> $referer = $_SERVER['HTTP_REFERER'];
> $access_code = $access_code - $access_code;
>
> /* FOR TEST ONLY */
> echo ("user id = " . $userid . "<br>");
> echo ("password = " . $password . "<br>"); echo ("account = " . $account
> .
> "<br>"); echo ("self = " . $self . "<br>");
>
> /* VALIDATE FOR BLANK INPUT FIELD */
> if( ( !$userid ) or ( !$password ) or (!$account) ) { header(
> "Location:$referer" ); exit(); } /*CONNECT TO MYSQL */
> $conn=@mysql_connect( "localhost", "paul", "enter" )
> or die( "Could not connect" );
> /* CONNECT TO DATABASE */
> $rs = @mysql_select_db( "test_db", $conn )
> or die( "Could not select database" );
>
> $rs = @mysql_select_db( "test_db", $conn ) or die( "Could not select
> database" );
>
> $sql = "SELECT access_code
> FROM authorised_users
> user_id = '$userid' AND
> user_password = '$password' AND
> account = '$account'";
>
> $rs = mysql_query( $sql, $conn ) or die( "Could not execute query" );
>
> $num = mysql_numrows( $rs );
>
> if( $num != 0 )
> { $access_code = access_code;
> echo ("testcheckpoint - Welcome - your log-in succeeded!" . "<br>");
> echo ("testcheckpoint - accesscode = " . access_code . "<BR>");
> echo ('testcheckpoint - $accesscode = ' . $access_code . "<BR>"); } else
> { echo (" test checkpoint statement 55 " . "<br>");
> header( "Location:$referer" );
> exit(); }
>
> ===========================================
> this is what is returned from the test
>
> user id = Nancy
> password = qwerty
> account = 48572998
> self = /tp_orth.php
> conn = Resource id #2
> sql = SELECT access_code FROM authorised_users WHERE user_id = 'Nancy' AND
> user_password = 'qwerty' AND account = '48572998'
> access = 0
> Welcome - your log-in succeeded!
> testcheckpoint - accesscode = access_code testcheckpoint - $accesscode =
> access_code
>
> I am trying to get the Access_code and cannot see what I am doing wrong
>
> P
>
>
>
>
>
>
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